Function SUM
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Function SUM
Hello,
I'have just begin testing this application, which looks great. But i got a question before buying the full version :
Is it possible to draw a 3d graph with with a SUM function, like
Z(X,Y) = SUM (from i=1 to X) of F(Y)
Where X is an integer
F(Y) = 1/(1+Y)^i
If not possible, do you have any idea where i could find an application able to do that?
Thx a lot
I'have just begin testing this application, which looks great. But i got a question before buying the full version :
Is it possible to draw a 3d graph with with a SUM function, like
Z(X,Y) = SUM (from i=1 to X) of F(Y)
Where X is an integer
F(Y) = 1/(1+Y)^i
If not possible, do you have any idea where i could find an application able to do that?
Thx a lot
JCAvella Guest
Re: Function SUM
It is certainly possible to do SUM with this software
Are you familiar with concept of recursive calls? Smart Math Calculator supports recursive calls and SUM is a special case of a recursive call. For example the Z(X,Y) = SUM (from i=1 to X) of 1/(1+Y)^i can be represented by:
Z(X,Y)=1/(1+Y)^X+Z(X1,Y) for as long as X is more than or equals to 1. I attached a screen shot of the complete set of expressions that address your question here:
I'm also displaying the Z(3,2) which is SUM (from i=1 to 3) of 1/(1+3)^i
which is
1/(1+2)^1+1/(1+2)^2+1/(1+2)^3 = 0.4815
As you can see the program also calculates the Z(3,2) to be 0.4815
Is this what you wanted?
Also let me know if this way is too complicated. We could create a simple SUM function for the next version.
cheers,
Saeid
Are you familiar with concept of recursive calls? Smart Math Calculator supports recursive calls and SUM is a special case of a recursive call. For example the Z(X,Y) = SUM (from i=1 to X) of 1/(1+Y)^i can be represented by:
Z(X,Y)=1/(1+Y)^X+Z(X1,Y) for as long as X is more than or equals to 1. I attached a screen shot of the complete set of expressions that address your question here:
I'm also displaying the Z(3,2) which is SUM (from i=1 to 3) of 1/(1+3)^i
which is
1/(1+2)^1+1/(1+2)^2+1/(1+2)^3 = 0.4815
As you can see the program also calculates the Z(3,2) to be 0.4815
Is this what you wanted?
Also let me know if this way is too complicated. We could create a simple SUM function for the next version.
cheers,
Saeid
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